Fill in the blank with a constant term to make the equation true.
1 answer:
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Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
Answers:
Step-by-step explanations:
Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.
<h3>What is an exponential function?</h3>A decaying exponential function is modeled by:
In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:
.
It halves in value at t years, for which A(t) = 0.5A(0), hence:
t = 5.42.
It takes 5.42 years for the car to halve in value.
More can be learned about exponential functions at brainly.com/question/25537936
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