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My name is Ann [436]
3 years ago
7

Which of the following decimal numbers are examples of terminating decimals?

Mathematics
2 answers:
krok68 [10]3 years ago
6 0

Answer:

I think it’s F, 0..6868

Step-by-step explanation:

Please give me brainliest

andrew11 [14]3 years ago
5 0

answer:

the answer to the question is c) 14.1

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What is 4.3% as a decimal
vfiekz [6]
0.043 is the correct answer :$
6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!
leva [86]

Answer:

11.7 units

Step-by-step explanation:

sq root(2--4)^2+(-7-3)^2

sq root(6)^2 + (-10)^2

sq root (36)+(100)

sq root 136

equals 11.66 which rounds up to 11.7

6 0
3 years ago
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The​ plate, including the bound
rjkz [21]

Answer:

We have the coldest value of temperature T(\frac{3}{4},0) = -9/16. and the hottest value is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x

Let's take the partials derivatives.

T_{x}(x,y)=2x-\frac{3}{2}=0

T_{y}(x,y)=4y=0

So, we can find the critical point (x,y) of T(x,y).

2x-\frac{3}{2}=0

x=\frac{3}{4}

4y=0

y=0

The critical point is (3/4,0) so the temperature at this point is: T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})

T(\frac{3}{4},0)=-\frac{9}{16}    

Now, we need to evaluate the boundary condition.

x^{2}+y^{2}=1

We can solve this equation for y and evaluate this value in the temperature.

y=\pm \sqrt{1-x^{2}}

T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x  

T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2

Now, let's find the critical point again, as we did above.

T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0            

x=-\frac{3}{4}    

Evaluating T(x,y) at this point, we have:

T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2  

T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}

Now, we can see that at point (3/4,0) we have the coldest value of temperature T(\frac{3}{4},0) = -9/16. On the other hand, at the point -(3/4),\frac{\sqrt{7}}{4}) we have the hottest value of temperature, it is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

I hope it helps you!

4 0
2 years ago
Pls help will give Brainiest
Ronch [10]

Answer:

-5

Step-by-step explanation:

8 0
2 years ago
26. The original price of Doritos is the same at both Wal-Mart and County Market. Jon found out that Wal-Mart had Doritos on sal
DerKrebs [107]
IDK sorry I couldn't help u
8 0
3 years ago
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