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Gnesinka [82]
3 years ago
7

Rob is saving to buy a new MP3 player. For every $16 he earns babysitting, he saves $9. On Saturday, Rob earned $96 babysitting.

How much money did he save?
Mathematics
2 answers:
Blizzard [7]3 years ago
8 0

Answer:

91

Step-by-step explanation:

brainliest plz

Ivenika [448]3 years ago
5 0

Answer:

91

Step-by-step explanation:

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Devon purchased tickets to an air show for 9 adults and 2
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18$ per adult, 15 per clild

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If it takes 33W of power to move a block for 3s, how much work is done
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These kittens get 1 can of cat food a day. If each can holds 6 ounces of food, how many ounces of food do they eat in one week?
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If 6=1 then 6x7= 42 so 42 oz of food per week
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A boogie board that has a regular price of $69 is on sale at a 35% discount. What is the sale price with 7% tax? Please show how
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If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?
Alisiya [41]
If k is odd, then

\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor

while if k is even, then the sum would be

\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4

The latter case is easier to solve:

\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0

which means k=6.

In the odd case, instead of considering the above equation we can consider the partial sums. If k is odd, then the sum of the even integers between 1 and k would be

S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)

Now consider the partial sum up to the second-to-last term,

S^*=2+4+6+\cdots+(k-5)+(k-3)

Subtracting this from the previous partial sum, we have

S-S^*=k-1

We're given that the sums must add to 2k, which means

S=2k
S^*=2(k-2)

But taking the differences now yields

S-S^*=2k-2(k-2)=4

and there is only one k for which k-1=4; namely, k=5. However, the sum of the even integers between 1 and 5 is 2+4=6, whereas 2k=10\neq6. So there are no solutions to this over the odd integers.
5 0
3 years ago
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