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Rudiy27
3 years ago
9

PLZZZZZ help me with this problem

Mathematics
1 answer:
katovenus [111]3 years ago
4 0

0.075.

Do the division on the fraction first, then add that to negative 1.125

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A poll in 2017 reported that 705 out of 1023 adults in a certain country believe that marijuana should be legalized. When this p
just olya [345]

Answer:

1. d. (0.652, 0.726)

2. b. (0.661, 0.718)

a. The margin of error of a 90​% confidence interval will be less than the margin of error for the 95​% and 99​% confidence intervals because intervals get wider with increasing confidence level.

Step-by-step explanation:

Data given and notation  

n=1023 represent the random sample taken in 2017    

X=705 represent the people who thinks that believe that marijuana should be legalized.

\hat p =\frac{705}{1023}=0.689 estimated proportion of people who thinks that believe that marijuana should be legalized.

z would represent the statistic in order to find the confidence interval    

p= population proportion of people who thinks that believe that marijuana should be legalized.

Part 1

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.689 -2.58 sqrt((0.689(1-0.689))/(1023))=0.652

0.689 + 2.58sqrt((0.56(1-0.689))/{1023))=0.726

And the 99% confidence interval would be given (0.652;0.726).

We are 99% confident that about 65.2% to 72.6% of people  believe that marijuana should be legalized

d. (0.652, 0.726)

Part 2

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.689 - 1.96((0.689(1-0.689))/(1023))=0.661

0.689 + 1.96 ((frac{0.56(1-0.689))/(1023))=0.718

And the 95% confidence interval would be given (0.661;0.718).

We are 95% confident that about 66.1% to 71.8% of people  believe that marijuana should be legalized

b. (0.661, 0.718)

Part 3

Would be lower since the quantile z_{\alpha/2} for a lower confidence is lower than a quantile for a higher confidence level.

The margin of error of a 90​% confidence interval will be less than the margin of error for the 95​% and 99​% confidence intervals

If we calculate the 90% interval we got:

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution. The quantile for this case would be 1.64.

And replacing into the confidence interval formula we got:

0.689 - 1.64 ((0.689(1-0.689))/{1023))=0.665

0.689 + 1.64 ((0.56(1-0.689))/(1023))=0.713

And the 90% confidence interval would be given (0.665;0.713).

We are 90% confident that about 66.5% to 71.3% of people  believe that marijuana should be legalized.

The intervals get wider with increasing confidence level.

So the correct answer is:

a. The margin of error of a 90​% confidence interval will be less than the margin of error for the 95​% and 99​% confidence intervals because intervals get wider with increasing confidence level.

6 0
3 years ago
PLEASE HELP ASAP <br>are f(x)=4/x-2-1 and g(x)=3/x+2-2 inverses of each other?​
GREYUIT [131]

Answer:

To find the inverse of:

f (x)=\dfrac{4}{x-2}-1

Set the function to y:

\implies y=\dfrac{4}{x-2}-1

Rearrange to make x the subject:

\implies y+1=\dfrac{4}{x-2}

\implies (y+1)(x-2)=4

\implies xy-2y+x-2=4

\implies xy+x=2y+6

\implies x(y+1)=2y+6

\implies x=\dfrac{2y+6}{y+1}

Swap x and y:

\implies y=\dfrac{2x+6}{x+1}

Change y to the inverse of the function sign:

\implies f\:^{-1}(x)=\dfrac{2x+6}{x+1}

Rewrite g(x) as a fraction:

g(x)=\dfrac{3}{x+2}-2

\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}

\implies g(x)=\dfrac{3-2(x+2)}{x+2}

\implies g(x)=\dfrac{3-2x-4}{x+2}

\implies g(x)=-\dfrac{2x+1}{x+2}

Therefore, as the inverse of f(x) ≠ g(x), the functions are NOT inverses of each other

4 0
2 years ago
Which statement about the equation is true x+2=x+4
DENIUS [597]
X cannot be solved.

This is not a solvable equation

no matter what, it will not equal

so your answer is unsolvable

hope this helps
3 0
3 years ago
Read 2 more answers
(x+4) (x+10)<br>simplify​
Murrr4er [49]

Answer:

x^2 + 14x + 40.

Step-by-step explanation:

(x+4) (x+10)

= x(x + 10) + 4(x + 10)     ( By the Distributive Law)

= x^2 + 10x + 4x + 40

= x^2 + 14x + 40.

8 0
3 years ago
Read 2 more answers
F(x) = −x + 5 with domain [−3, 2] What is the range
Anna71 [15]
All real numbers is the awnser
5 0
2 years ago
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