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Dahasolnce [82]
3 years ago
9

Please answer! I crossed out the ones you don’t have to complete.

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

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A fruit company delivers its fruit in two types of boxes: large and small. A delivery of eight large boxes and four small boxes
vazorg [7]

Answer:

Weight of Large Box = 18.5 kg

Weight of Large Box = 13.25 kg

Step-by-step explanation:

<u>Given:</u>

There are two types of boxes i.e. Large and Small

Let the weight of Large boxes = L kg

Let the weight of Small boxes = S kg

As per given statement:

  • A delivery of eight large boxes and four small boxes has a total weight of two hundred and one kilograms.

Writing equation for above:

8L + 4S = 201 ....... (1)

  • A delivery of three large boxes and two small boxes has a total weight of eighty two kilograms.

Writing equation for above:

3L + 2S = 82 ....... (2)

Now, by solving the equations (1) and (2), we can get the values of L and S.

<em>Multiplying equation (2) with 2 and subtracting from equation (1):</em>

8L + 4S = 201

-

2 \times (3L + 2S) = 82 \times 2

8L + 4S = 201

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6L + 4S = 164

--------------------

2L = 37

L = 18.5 Kg

Putting value of L in equation (1):

8 \times 18.5 + 4S = 201\\\Rightarrow 148 + 4S = 201\\\Rightarrow  4S = 201 - 148\\\Rightarrow  4S = 53\\\Rightarrow S = 13.25\ kg

So, the answer is:

Weight of Large Box = 18.5 kg

Weight of Large Box = 13.25 kg

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Answer:

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Step-by-step explanation:

A. is the answer because they list all of the sandwiches, soups, and beverages with every possible combination.

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