Question

What is an equation of the line that passes through the point (-5 7) and is parallel to the line x-5y=15

Answer 1

Answer:

Step-by-step explanation:

Parallel lines have same slope.

y = mx + b

Slope = m  & y-intercept = b

x - 5y = 15

   -5y = -x + 15

      y = $\frac{-1}{-5}x + \frac{15}{-5}$

$y = \frac{1}{5}x - 3$

so, slope = 1/5   ; (-5 , 7)

y -y1 = m(x -x1)

$y - 7 = \frac{1}{5}(x- [-5])\\\\y - 7 =\frac{1}{5}(x + 5)\\\\y - 7 = \frac{1}{5}x+5*\frac{1}{5}\\\\y - 7 =\frac{1}{5}x+1\\\\y =\frac{1}{5}x+1+7\\\\y=\frac{1}{5}x + 8$