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Grace [21]
3 years ago
7

Tom has 28 milk chocolates and emily has 24 dark chocolates they have to divide these chocolates into small packets that each ha

ve the same number of dark chocolates and the same number of milk chocolates
The maximum number of packets they can make is ___To make the maximum number of packets, each packet should have___ milk chocolates and ___
dark chocolates.
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0
28+24=52
So we make a sum of what's going to equal 52 in small packets.
I found 4x13=52. 13 would be the number of packets......
BUT!! Since it MUST be equal dark and milk and we have 28 and 26,
you would have to eliminate 1 pack because all 4 would be milk chocolate.
So that is only 12 packets.
4 per pack so that would be 2 dark and 2 milk per packet.
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How to solve 4/7y-2 = 3/7 + 3/14
lisabon 2012 [21]
Solution

1) Simplify \frac{4}{7y}<span> to </span>\frac{4y}{7}
\frac{4y}{7} <span>−2= </span>\frac{3}{7} + \frac{3}{14}

2) Simplify \frac{3}{7} + \frac{3}{14} <span>to <span>914</span>
</span>\frac{4y}{7} <span>−2= </span>\frac{9}{14}

3) <span>Add 2 to both sides
</span>\frac{4y}{7} = \frac{9}{14} <span>+2
</span>
4) Simplify \frac{9}{14&#10;} <span><span>+2</span> to </span>\frac{37}{14}
\frac{4y}{7} = \frac{37}{14}

5) <span>Multiply both sides by 7
</span><span>4y= </span>\frac{37}{14} <span>×7
</span>
6) Simplify \frac{37}{14} <span><span>×7</span> to </span>\frac{259}{14}
\frac{4y}{7} =\frac{259}{14}

7) Simplify \frac{259}{14}<span> to </span>\frac{37}{2}
\frac{4y}{7} = \frac{37}{2}

8) <span>Divide both sides by 4
</span>y= \frac{37}{2} <span>×4
</span>
9) <span>Simplify <span>2×4</span> to 8
</span><span>y=</span>\frac{37}{8}
<span><span>
Hope this helps 

</span></span>
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Deborah has two paintings in her portfolio and paints three more each week.Kai has twelve paintings in her portfolio and paints
elena-14-01-66 [18.8K]
Well, we can set up these equations like this-
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Kai- 12+2w
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Now, we set them equal to each other:
2+3w=12+2w

Solve for w
2-12=2w-3w
-10 = -1w
w = 10
10 weeks. Hope this helped!
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