Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Hi, It is simple:
Sin(A) = a / c
Cos(A) = b / c
Tan(B) = b / a
Sin(J) = j / i
Cos(K) = j / i
Tan(K) = k / j
This are the answers
Answer:
82
Step-by-step explanation:
let X = the number of hamburgers sold
let Y = the number of cheeseburgers sold a combined total of 328 were sold
so: X + Y = 328
cheeseburgers = 3 times the number of hamburgers sold
so: Y = 3X
substitute 3X into the equation for Y
X + 3X = 328
4X = 328
divide both sides by 4 to get the variable X by itself
X = 82
so: 82 hamburgers were sold Friday
Answer:
The value of P-value is 0.0472.
Step-by-step explanation:
We are given that you take a simple random sample of 12 apartments in town A and calculate the average price of these apartments. You repeat this for 15 apartments in town B.
Let
= <u><em>true average price of apartments in town A</em></u>
= <u><em>true average price of apartments in town B</em></u>
So, Null Hypothesis,
:
Alternate Hypothesis,
:
The test statistics that have been used here is <u>two-sample t-test statistics</u>, i.e;
The test statistics given to us is 2.1
Now, the P-value of the test statistics is given by the following formula;
P-value = P(
> 2.1)
= P(
> 2.1) = 0.0236
In two-tailed test, P-value is calculated as = 2
0.0236 = <u>0.0472</u>
Hence, the value of the p-value is 0.0472.
See attachment for answer and math work.