the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
Answer:
Class 2 has 210 house points.
Step-by-step explanation:
630/3 = 210
1 = 210 x 2 = 420
2 = 210
420 + 210 + 630
We need to simpify the given expression. The given expression to us is ,
<u>Given </u><u>Expression</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Using </u><u>Identity</u><u> </u><u>:</u><u>-</u><u> </u>
<u>So </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>
<u>We </u><u>have</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>-</u><u>1</u><u>/</u><u>4</u><u>. </u>