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jeka94
3 years ago
13

HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP

Mathematics
2 answers:
Lelu [443]3 years ago
5 0
4^25/4^15 which simplified is 1^10.
balu736 [363]3 years ago
4 0

Answer:

ok, so two to the 19th power is 524,288, 2 to the 5th power is 32. 524,228 x 32=16,775,296.

2 to the 12th power is 4096, 3 to the 3rd power is 8, 4096 x 8=32,768.

16,775,296/32,768

after that just simplify.

hopefully my answ helps, i think i did it correctly, my brain is ded

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Which equation is equivalent to 8x +3(x-5) -5(x -4)<br> 6x+35<br> 6x +1<br> 6x -5<br> 43x
user100 [1]

Step-by-step explanation:

8x+3x-15-5x+20

6x+5

I think correct answer is 6x+5

7 0
3 years ago
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Butternut is a ski resort in massachusetts. one of their triple chair lifts unloads 1296 skiers per hour at the top of the slope
Andrews [41]
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7 0
4 years ago
What is the volume of a hemisphere with a radius of 48 m, rounded to the nearest tenth of a cubic meter
Thepotemich [5.8K]

Answer:

The volume of the hemisphere is approximately 231,623.3 m³

Step-by-step explanation:

The radius of the hemisphere in the question, r = 48 m

A hemisphere is obtained by sharing a sphere into two halves

The radius of the hemisphere = The radius of the sphere which describes it

∴ The volume of a hemisphere = The volume of a sphere ÷ 2

The volume of a sphere = (4/3)·π·r³

∴ The volume of a hemisphere = (4/3)·π·r³ ÷ 2 =  (2/3)·π·r³

∴ The volume of the given hemisphere with 48 m radius, V = (2/3) × π × 48³

∴ V = (2/3) × π × (48 m)³ = 231,623.343164 m³

When the measure of the volume of the hemisphere is rounded to the nearest tenth, we have, V ≈ 231,623.3 m³.

5 0
3 years ago
Screenshot with answers included A circle has a radius of 1 cm.
lora16 [44]
Area = \pi  r^{2} 
area =  \pi x 1 x 1 = \pi 

Circumference = 2\pi r
Circumference = 2 x \pi x1
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The circumference is greater than the area


6 0
4 years ago
If f(x) = 3x^2 - 1 and g(x) = 4x + 2, then what is f(g(x))?
Gelneren [198K]

Answer:

(f + g) (2) = -4(f+g)(2)=−4

Step-by-step explanation:

We have the functions

F(x) =-3x^2-2F(x)=−3x2−2   And  g(x)=4x+2g(x)=4x+2

We want to find

(f + g) (x)(f+g)(x)

Then

\begin{gathered}(f+g)(x) = f(x) + g(x)\\\\(f+g)(x) = -3x^2-2 + 4x+2\\\\(f+g)(x)= -3x^2 +4x\end{gathered}(f+g)(x)=f(x)+g(x)(f+g)(x)=−3x2−2+4x+2(f+g)(x)=−3x2+4x

finally we find

(f + g) (2)(f+g)(2)

\begin{gathered}(f + g) (2) = -3(2)^2 + 4(2)\\\\(f + g) (2) = -3*4 + 8\\\\(f + g) (2) = -12+ 8\\\\(f + g) (2) = -4\end{gathered}(f+g)(2)=−3(2)2+4(2)(f+g)(2)=−3∗4+8(f+g)(2)=−12+8(f+g)(2)=−4

8 0
3 years ago
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