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Ivenika [448]
3 years ago
6

What’s the measure of angle X?

Mathematics
1 answer:
Arada [10]3 years ago
4 0

Answer:

x = 84°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

129° is an exterior angle of the triangle, thus

x + 45° = 129° ( subtract 45° from both sides )

x = 84°

The 2 triangles formed by the tree/ shadow and Jordan/ shadow are similar and ratio of corresponding sides are equal, that is

let h be the height of the tree, then

\frac{h}{7} = \frac{50}{10} = 5 ( multiply both sides by 7 )

h = 35

The height of the tree is 35 ft

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Try this solution, it consists of two parts (MN=8).

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Which polynomial is in standard form
sukhopar [10]

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7 0
3 years ago
Which expression is equivalent to...
olga_2 [115]

Answer:

8m^5

Step-by-step explanation:

Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)

This gives us the fraction: \frac{24m^7}{3m^2}

We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction: \frac{24 * m * m * m * m * m * m * m}{3 * m * m}

Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:

\frac{24 * m * m * m * m * m}{3} which can be simplified in exponent form as: \frac{24m^5}{3}, now all we have to do is divide the 24 by the 3, to get 8

This gives us the answer: 8m^5

6 0
1 year ago
<img src="https://tex.z-dn.net/?f=%5Csf%202x%2B7%2B8x%3D35" id="TexFormula1" title="\sf 2x+7+8x=35" alt="\sf 2x+7+8x=35" align="
Dafna11 [192]

Answer:

x=14/5

Step-by-step explanation:

Group like terms

2x+8x+7=35

Add similar elements: 2x+8x=10x

10x+7=35

Subtract 7 from both sides:

10x+7−7=35−7

Simplify

10x=28

Divide both sides by 10

10x/10 =28/10

Simplify:

x=14/5

7 0
3 years ago
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