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FinnZ [79.3K]
3 years ago
8

HELP ME PLEASE GIVE RIGHT ANSWER WILL GIVE BRAINLIEST

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

a. The point of the vertex is (h, k)

b. The equation of the line of symmetry is x=h

c. You can tell if the parabola goes up and down by checking if a is positive or negative: if it is positive then it goes up, and it goes down otherwise.

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-4b/19=32/19

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☆15 POINTS AND MARKED BRAINLIEST IF CORRECT☆<br>look at the image above to view the question!​
swat32

Answer:

3125 bacteria.

Step-by-step explanation:

We can write an exponential function to represent the situation.

We know that the current population is 100,000.

The population doubles each day.

The standard exponential function is given by:

P(t)=a(r)^t

Since our current population is 100,000, a = 100000.

Since our rate is doubling, r = 2.

So:

P(t)=100000(2)^t

We want to find the population five days ago.

So, we can say that t = -5. The negative represent the number of days that has passed.

Therefore:

\displaystyle P(-5)=100000(2)^{-5} = 100000 \Big( \frac{1}{32}\Big)  = 3125 \text{ bacteria}

However, we dealing within this context, we really can't have negative days. Although it works in this case, it can cause some confusion. So, let's write a function based on the original population.

We know that the bacterial population had been doubling for 5 days. Let A represent the initial population. So, our function is:

P(t)=A(2)^t

After 5 days, we reach the 100,000 population. So, when t = 5, P(t) = 100000:

100000=A(2)^5

And solving for A, we acquire:

\displaystyle A=\frac{100000}{2^5}=3125

So, our function in terms of the original day is:

P (t) = 3125 (2)^t

So, it becomes apparent that the initial population (or the population 5 days ago) is 3125 bacteria.

3 0
3 years ago
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7 0
3 years ago
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