Answer: K= 8/3 or 2 2/3
Step-by-step explanation:
Answer:
D. x = 5.4, y = 6.67
Step-by-step explanation:
The triangles are similar as per problem description, so the ratios match:
y/5 = 4/3
x/3 = 9/5
let's solve:
y/5 = 4/3
3y/5 = 4
3y = 20
y = 6.(6)
x/3 = 9/5
5x/3 = 9
5x = 27
x = 5.4
Answer:11.5
Step-by-step explanation:
distance=6 2/5 + 2 3/4 + 2 1/3
d=(5x6+2)/5 + (4x2+3)/4 + (3x2+1)/3
d=32/5 + 11/4 + 7/3
d=(12x32+15x11+20x7) ➗ 60
d=(384+165+140) ➗ 60
d=689 ➗ 60
d=11.5
Answer:
35 different routes
Step-by-step explanation:
The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.
Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.
The number of combinations of n objects taken r at a time is: ⁿCᵣ
So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by
⁷C₄ = 35 different ways.
Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.
Hope this Helps!!!
