Question

At a certain university, 42% of the students are women and 18% of the students are engineering majors. Of the engineers, 22% are women. If a student at this university is selected at random, what is the probability that the selected person is a woman engineering major?

Answer 1

Answer:

The probability that the selected person is a woman engineering major is 0.0396.

Step-by-step explanation:

The proportion of students at the university who are women is 0.42.

P (W) = 0.42

The proportion of students at the university who are engineering majors is 0.18.

P (E) = 0.18

The proportion of engineering majors that are women is 0.22.

P (W|E) = 0.22

The proportion of students at the university that are woman and engineering major is:

$P (W|E)=\frac{P(W\cap E)}{P(E)} \\P(W\cap E)=P(W|E)\times P(E)\\= 0.18\times0.22\\=0.0396$

Thus, the probability that the selected person is a woman engineering major is 0.0396.