All categories

2 years ago

Plz help me with this???

Mathematics

2 answers:

Monica [59]2 years ago

7 0

Answer:

$\frac{9}{28}$

Step-by-step explanation:

Shaded area = 1 - $\frac{1}{4}$ - $\frac{3}{7}$ (Make them have the same denominator, 28)

= $\frac{28}{28}$ - $\frac{7}{28}$ - $\frac{12}{28}$ (Simplify)

= $\frac{28}{28}$ - $\frac{19}{28}$ (Evaluate)

= $\frac{9}{28}$

ludmilkaskok [199]2 years ago

7 0

Answer:

9/28 is the answer

Step-by-step explanation:

it maybe really late.

You might be interested in

Can sum kne s help I need it

Reika [66]

The answer is 1 no solution

3 0

2 years ago

Read 2 more answers

The entrance fee to the national park is $15. The campsite fee is $25 per night.

lisabon 2012 [21]

Answer:

Step-by-step explanation:

a.) y = 25x + 15

b.) y is the total cost x is the amount of nights stayed 15 is the entrance fee and 25 is the cost per night

i.) x is the amount of nights stayed y is the total cost

ii.) slope (or m) is 25 y-intercept is 15

c.) plug in 3 for x

y = 25(3) + 15

y = 75 + 15

y = 90

its $90 for 3 nights

hope this helps <3

8 0

2 years ago

A recipe that makes 7 servings calls for 1 1/6 cups of juice.

VMariaS [17]

1/7 cups per serving

6 0

2 years ago

In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population

Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

$y=a(1+r)^{t}$

Here,

y = final value

a = initial value

r = growth rate

t = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of r as follows:

$y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145$

Now, compute the time it will take the population to grow to 800 insects as follows:

$800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17$

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0

2 years ago

Solve for x in the equation: x^2 - x = 20

max2010maxim [7]

X=5
cuz 5^2=25
25-5=20

8 0

2 years ago