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3 years ago

Plz help me with this???

Mathematics

2 answers:

Monica [59]3 years ago

7 0

Answer:

$\frac{9}{28}$

Step-by-step explanation:

Shaded area = 1 - $\frac{1}{4}$ - $\frac{3}{7}$ (Make them have the same denominator, 28)

= $\frac{28}{28}$ - $\frac{7}{28}$ - $\frac{12}{28}$ (Simplify)

= $\frac{28}{28}$ - $\frac{19}{28}$ (Evaluate)

= $\frac{9}{28}$

ludmilkaskok [199]3 years ago

7 0

Answer:

9/28 is the answer

Step-by-step explanation:

it maybe really late.

You might be interested in

Find the area of the figure.

Slav-nsk [51]

Answer:

132cm

Step-by-step explanation:

Split there firgue into shapes you know

there is a rectangle and a Trapezoid

A = bh

A = 7×4

A = 28cm

Trapezoid

A = 1/2h(b+b)

A = 1/2×8(19+7)

A = 1/2×8(26)

A = 1/2(208)

A = 104cm

Add them together

104 + 28 = 132

4 0

3 years ago

Read 2 more answers

1 Katherine can run the perimeter of Kiker Park in

Vlad1618 [11]

The according to the perimeter, Parker takes 5 second longer than the Marin to run the perimeter.

According to the statement

We have to find that the comparison of the running time of the parker.

So, For this purpose, we know that the

Perimeter is the distance around the edge of a shape.

From the given information:

Katherine can run the perimeter of Kiker Park in 5.0 minutes and It takes Marin 1.45 minutes longer.

Marin takes 6.45 minutes and the Parker can run the perimeter of the park in 6.50 minutes.

Then from the statement it is clear that the

Time taken by Katherine = 5.0 minutes

Time taken by Parker = 6.50 minutes

Time taken by Marin = 5.0 minutes + 1.45 minutes

Time taken by Marin = 6.45 minutes.

from the timing we can say that the Marin's running time to Parker's running time is compared and the Parker takes 5 seconds more than the Marin.

So, The according to the perimeter, Parker takes 5 second longer than the Marin to run the perimeter.

Learn more about Perimeter here

brainly.com/question/19819849

#SPJ9

5 0

1 year ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial: