All categories

3 years ago

Plz help me with this???

Mathematics

2 answers:

Monica [59]3 years ago

7 0

Answer:

$\frac{9}{28}$

Step-by-step explanation:

Shaded area = 1 - $\frac{1}{4}$ - $\frac{3}{7}$ (Make them have the same denominator, 28)

= $\frac{28}{28}$ - $\frac{7}{28}$ - $\frac{12}{28}$ (Simplify)

= $\frac{28}{28}$ - $\frac{19}{28}$ (Evaluate)

= $\frac{9}{28}$

ludmilkaskok [199]3 years ago

7 0

Answer:

9/28 is the answer

Step-by-step explanation:

it maybe really late.

You might be interested in

A scientist is studying red maple tree growth in a state park. She measured the trunk diameters of a sample of trees in the same

Natali5045456 [20]

Point b is the correct answer love!

4 0

3 years ago

✨Please help it would mean a lot!:)✨

DENIUS [597]

Answer:

x=6.5

y= -.5

Step-by-step explanation:

Plug it in and see if it works to make sure. Good luck

3 0

2 years ago

Read 2 more answers

Solve -5(-5m + 5) = -2m – 4

skad [1K]

Answer:

m=7/9

Step-by-step explanation:

-5(-5m+5)=-2m-4

25m-25=-2m-4

25m+2m=-4+25

27m=21

÷ 27 ÷ 27 (divide both sides)

m=7/9 or .777 (infinite)

7 0

3 years ago

Which is a solution for the equation 3x + 13 = 73?

sweet [91]

Answer:

x=20

Step-by-step explanation:

73-13=60

60÷3=20

7 0

3 years ago

Read 2 more answers

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

8 0

3 years ago

Read 2 more answers