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Assoli18 [71]
2 years ago
5

Find the volume: 5ft 5ft 8ft 3ft ​

Mathematics
1 answer:
andreev551 [17]2 years ago
3 0

Answer:

120ft

Step-by-step explanation:

8 x 3 x 5

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kirill [66]

Answer:

Question 11.1

At 7 : 00 pm in Sydney, it will be 10 : 00 pm in Berlin.

Question 11.2

Place | Time

Sydney | 5 : 00 pm

Berlin | 8 : 00 pm

It would be a good time for Mark and Hans to cha,t when it's 5 : 00 pm in Sydney and 8 : 00 pm in Berlin.

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5 0
2 years ago
Through: (3, -5) and (0, -2) <br><br><br>please add the steps please.​
Vlad [161]
1: -5 = 3m + c
2: -2 = 0 + c

From equation 2, we knew c = -2
So we sub into equation 1 and got the value of m

-5 = 3m - 2
m = -1

The equation of line is y = -x - 2
7 0
2 years ago
Identify the domain of the function.<br> (-4,4)<br> [-4,4)<br> (-4,4)<br> (-4, 4)
Vlad1618 [11]
All real numbers I think
3 0
3 years ago
WILL GIVE BRAINLIEST!!!!!!!!!!!! 20 points
irina [24]

Answer:

if they are same exact thing but mirrored, then just mirror it the way it needs to.

Example

-1 in the second by -3.4, 3.4 by  1

5 0
2 years ago
Please help this is important for me.
Anit [1.1K]
<h3>Answer: point Q is located at (-1, 1)</h3>

=================================================

Explanation:

Check out the diagram below.

Plot R(-3,7) and T(3,-11) on the same xy grid.

Draw a vertical line through R and a horizontal line through T. A right triangle forms. At the intersection point is point S(-3,-11)

----------------------

Now measure the distance from point S to point T. You can count out the spaces or subtract the x coordinates and use absolute value.

|x1-x2| = |-3-3| = |-6| = 6

From point S to point T is 6 units.

We want to subdivide this horizontal length in the ratio 1:2

What this means is that we want to plot a point U somewhere such that SU:UT = 1:2

In other words,

SU = x

UT = 2x

SU+UT = ST

x+2x = 6

3x = 6

x = 6/3

x = 2

So we must move 2 spaces to the right from point S to get to U(-1,-11)

Going from point U(-1,-11) to T(3,-11) is 4 spaces

We have SU:UT = 2:4 = 1:2 to help confirm we have the correct location for point U

From point U, we then move straight up to the line segment RT

We'll land on Q(-1,1)

----------------------

Another way to find the y coordinate of point Q is to subdivide the segment RS into the ratio 1:2 similar to how we divided ST up

Segment RS is 18 units long since we go from y = 7 to y = -11 when going from R to S.

If V was on segment RS such that

RV:VS = 1:2

and RV = y

then

RV+VS = RS

y+2y = 18

3y = 18

y = 6

RV = y = 6

VS = 2y = 2*6 = 12

So you'll move 6 units down from y = 7 to land on y = 1 (when going from the y coordinate of R to the y coordinate of Q)

3 0
3 years ago
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