Answer:
Perimeter of PQR = 37 units (Approx.)
Step-by-step explanation:
Using graph;
Coordinate of P = (-2 , -4)
Coordinate of Q = (16 , -4)
Coordinate of R = (7 , -7)
Find:
Perimeter of PQR
Computation:
Distance between two point = √(x1 - x2)² + (y1 - y2)²
Distance between PQ = √(-2 - 16)² + (-4 - 4)²
Distance between PQ = 18 unit
Distance between QR = √(16 - 7)² + (-4 + 7)²
Distance between QR = √81 + 9
Distance between QR = 9.48 unit (Approx.)
Distance between RP = √(7 + 2)² + (-7 + 4)²
Distance between RP = √81 + 9
Distance between RP = 9.48 unit (Approx.)
Perimeter of PQR = PQ + QR + RP
Perimeter of PQR = 18 + 9.48 + 9.48
Perimeter of PQR = 36.96
Perimeter of PQR = 37 units (Approx.)
Answer:
She will have $25.00 in her bank account!
Step-by-step explanation:
If she has -$50 and adds 75 that is filling in the negative hole and adding $25 to the 0 she would have. ;) hope this helps!
Answer:
B(6 , -11)
Step-by-step explanation:
(x-2 , y+3) = (4 , -8)
Compare the x & y co ordinates
x - 2 = 4 ; y + 3 = -8
x = 4 +2 ; y = -8 - 3
x = 6 ; y = -11
B(6 , -11)
Complete Question
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Answer:
16.5°
Step-by-step explanation:
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
We solve using Sine rule formula
a/sin A = b/sin B
We are solving for angle W
∠V=136°
Hence:
22 /sin 136 = 9 /sin W
Cross Multiply
22 × sin W = sin 136 × 9
sin W = sin 136 × 9/22
W = arc sin [sin 136 × 9/2.2]
W = 16.50975°
W = 16.5°
