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Ugo [173]
3 years ago
11

Which equation represents a line that passes through the two points in the

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
(3,3) and (6,5)
find slope
5-3/6-3=2-3=m so the answer is either a or d

now for point slope (3,3) was used so the correct equation would be
y-3=2/3(x-3) which is a!!
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What is the area of sector GPHthe area of the sector GPH is __ square yards. in exact terms of pi
finlep [7]

The Solution:

Given:

We are required to find the area of the sector GPH.

The formula for the area of sector GPH is:

\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\  \\ \text{ In this case,} \\ \theta=40^o \\ r=radius=15yards \\ A=area=? \end{gathered}

Substitute these values in the formula.

A=\frac{40}{360}\times\pi\times15^2=\frac{15^2\pi}{9}=25\pi\text{ }yards^2

Therefore, the correct answer is:

8 0
2 years ago
What is the ​ IQR ​ for the data set? {61, 70, 59, 55, 69, 59, 62} Drag and drop the correct answer into the box.
True [87]

Answer:

10

Step-by-step explanation:

Interquartile Range Formula:

IQR = Q3 - Q1

Quartiles Quartiles:

Q1 --> 59

Q2 --> 61

Q3 --> 69

69 - 59 = 10

[RevyBreeze]

5 0
2 years ago
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Find the area of the figure. Round to the nearest hundredth when necessary
dexar [7]

Answer:

  745.44 square mm

Step-by-step explanation:

The figure can be decomposed into ...

  • a semicircle of radius 12.5 mm
  • a rectangle 12.5 mm by 25 mm
  • a triangle 12.5 mm by 30 mm

The relevant area formulas are ...

  Semicircle: A = 1/2πr² = 1/2π(12.5 mm)² ≈ 245.437 mm²

  Rectangle: A = LW = (12.5 mm)(25 mm) = 312.500 mm²

  Triangle: A = 1/2bh = 1/2(12.5 mm)(30 mm) = 187.500 mm²

Total area of the figure is ...

  245.437 +312.500 +187.500 = 745.437 . . . mm²

The area of the figure is about 745.44 square mm.

6 0
4 years ago
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Need help please some one
ella [17]

Answer:

gforse

Step-by-step explanation: 660

5 0
3 years ago
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Referring to the Fig. in Question #40, find the unknown<br> length Y.
icang [17]

Answer:

tan30°=7/x

\frac{1}{ \sqrt{3} }  =  \frac{7}{x }  \\ x = 7 \sqrt{3}

cos30°=x/y

\frac{ \sqrt{3} }{2}   =  \frac{7 \sqrt{3} }{y}  \\  \\ 7 \sqrt{3}  \times 2 =  \sqrt{3}  \times y \\ \frac{7 \sqrt{3 }  \times 2}{ \sqrt{3} }  = y \\7 \times 2 = y \\ 14 = y

tell me if it's wrong.

7 0
2 years ago
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