-4x-3y-9=0
|| m1 = - ( - 4)/-3= - 4/3
_|_ m2 = -1/m1= 3/4
2x+4y-3=0
|| m1= -2/4= -1/2
_|_ m2= 2
12x-y-17=0
|| m1= -12/-1=12
_|_ m2 = -1/12
x-y=0
|| m1= -1/-1=1
_|_ m2= -1
8x - 3y - 2=0
|| m1= -8/-3= 8/3
_|_ m2 = -3/8
-2x + y - 5=0
|| m1= -(-2)/1=2
_|_ m2= -1/2
Answer:
x>2 or x<-10
Step-by-step explanation:
9|x +4|>54
Divide each side by 9
9/9|x +4|>54/9
|x +4|>6
There are two solutions, one positive and one negative
x+4 >6 or x+4 < -6
Subtract 4 from each side
x+4-4 >6-4 or x+4-4 < -6-4
x>2 or x<-10
h(x) = 3^x – 2 will be negative when x is less than 0
h(2) =7
g(2)=7
This is the point they are equal
g(x)> h(x) until2
g(x)>=h(x) -2<=x<=2
Choice A
