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3 years ago

Solve for d. 6(d+1)−2d=54 Enter your answer in the box.

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

D = 12 the answer is 12

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Solve for n:<br> (n+4)/10 = (n-8)/2

nalin [4]

Answer:

n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

(n+4) * 2 = 10 * ( n-8)

Distribute

2n+8 = 10n -80

Subtract 2n from each side

2n+8-2n = 10n-80-2n

8 = 8n-80

Add 80 to each side

8+80= 8n-80+80

88 = 8n

Divide each side by 8

88/8 = 8n/8

11 = n

4 0

1 year ago

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7th grade math help me pleaseeee

horsena [70]

Answer:

-11

Step-by-step explanation:

7 0

3 years ago

Given the two expressions shown below:

Alchen [17]

A is irrational but b is rational. This is because for b you can work out both square root of 64 (8) and square root of 4 (2). But for a, the square root of 5 is an irrational number :)

5 0

3 years ago

How to integrate absolute value.

wolverine [178]

Answer:

I cant even see anything can you reupload your answer, please?

Step-by-step explanation:

6 0

2 years ago

Please reference attached image for the problem that requires solving. Thank you so much for taking the time to help.

Lemur [1.5K]

Explanation:

The number of times the 6-sided number cube will be rolled will is

$750$

Let the numbers greater than 4 be represented below as

$E_1$ $\begin{gathered} E_1=\lbrace5,6\rbrace \\ n(E_1)=2 \end{gathered}$

The number of sample space will be

$n(S)=6$

The probability of rolling a number greater than 4 will be calculated below as

$\begin{gathered} Pr(E_1)=\frac{n(E_1)}{n(S)} \\ Pr(E_1)=\frac{2}{6}=\frac{1}{3} \end{gathered}$

Hence,

To calculate the number of times a number greater than 4 will be rolled will be calculated below as

$\begin{gathered} =Pr(E_1)\times750 \\ =\frac{1}{3}\times750 \\ =250times \end{gathered}$

Hence,

The final answer is

$\Rightarrow250\text{ }times$

5 0

1 year ago