You would use the Pythagorean there on which is a^2+b^2=c^2, from there you plug int what they gave you and solve for b, and b=12
I believe the answer is C
Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
Answer:
$70
Step-by-step explanation:
Middletown Equation:
1c +50 = T
Sweet Shoppe Equation:
2c + 30 = T
Set equations equal to one another and solve for first for cupcakes then for cost.
1c + 50 = 2c + 30
c+ 20 = 2c
20 = c (twenty cupcakes would be ordered)
Now insert into either equation ( or both to check)
1(20) + 50 = 70
2(20)+ 30 = 70
Total cost would be $70
HOPE THIS HELPS!!!
You set 49 equal to 8x - 15
So
8x - 15 = 49
+15 + 15
8x = 64
Then divide by 8
X= 8
