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3 years ago

Decide!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

slega [8]3 years ago

7 0

Answer:

1458

Step-by-step explanation:

As per the question we are looking for a number which is a multiple of the greatest possible exponent of 3.

Let's see the exponents of 3 within 1-2017 interval:

3¹ = 3, 3²= 9, 3³ = 27, 3⁴ = 81, 3⁵ = 243, 3⁶ = 729, 3⁷ = 2187 > 2017

As we see the greatest exponent of 3 is 729.

There are two multiples of 729 in the given interval:

729*1 = 729 and 729*2 = 1458

So the last number is 1458

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