The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
The image is missing, so i have attached it.
Answer:
x = 56.44°
Step-by-step explanation:
From the attached image, we can see that this is a right angle triangle which has opposite, adjacent and hypotenuse as sides. Since we want to find the angle x, thus, we can make use of trigonometric ratios.
From the attached image, the side opposite to angle x is 10ft and the hypotenuse is 12 ft.
From trigonometric ratios, we know that, sin x = opposite/hypotenuse
So, sin x = 10/12
x = sin^(-1) (10/12)
x = sin^(-1) 0.8333
x = 56.44°
Step-by-step explanation:
1/4
90%
1.5
0.005
6/10
25%
2/10
49.5
3/4
0.4
Answer:
$1.95
Step-by-step explanation:
notebook = n
pencil = p
3n + 2p = 5.10
2n + 3p = 4.65
multiply top equation by 2 and bottom by 3
6n + 4p = 10.20
6n +9p = 13.95
subtract bottom equation from the top equation
-5p = -3.75
divide by 5, negatives cancel out
p = 0.75
sub p into either equation, I chose the original top equation
3n + 2(0.75) = 5.10
3n + 1.50 = 5.10
subtract 1.50 from both sides
3n = 3.60
divide both sides by 3
n = 1.20
p = 0.75
n + p = 1.95 (the fourth option)
Answer:
If a and b are two positive rational numbers such that ab is not a perfect square of a rational number, then ab is an irrational number lying between a and b.
So an irrational number between 3 and 4 is=3×4=3×4=3×2=23