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3 years ago

how is the formula for the area of a trapezoid related to the formula for the area of a parallelogram?

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

They are related becasue if you find the area of a parallelogram then divide it by two then you have the area of a triangle

Step-by-step explanation:

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Complete the point-slope equation of the line through (2,3)(2,3)left parenthesis, 2, comma, 3, right parenthesis and (7,4)(7,4)l

vovikov84 [41]

Answer:

$y = \frac{1}{5}x +\frac{13}{5}$

Step-by-step explanation:

Given

$(x_1,y_1) = (2,3)$

$(x_2,y_2) = (7,4)$

Required

Complete the equation y - 4.....

First, we need to determine the slope as follows:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{4 - 3}{7 - 2}$

$m = \frac{1}{5}$

The equation is then calculated as thus:

$y - y_1 = m(x - x_1)$

This gives:

$y - 4 = \frac{1}{5}(x -7)$

Open bracket

$y - 4 = \frac{1}{5}x -\frac{7}{5}$

Add 4 to both sides

$y - 4 +4= \frac{1}{5}x -\frac{7}{5} + 4$

$y = \frac{1}{5}x -\frac{7}{5} + 4$

$y = \frac{1}{5}x +\frac{-7+20}{5}$

$y = \frac{1}{5}x +\frac{13}{5}$

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3 years ago

The area of the following rectangle is 6O and^4 square meters and its length is 30 and meters

blsea [12.9K]

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3 years ago

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

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It depends on what contract you are signing if you are having doubts then yes but not then no!

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