A circle with a diameter 28m. Find it area and circumference Take[Π=3.4]
1 answer:
Diameter of a circle = 28 m
Then, radius of the circle will be :
Thus, the radius of this circle = 14 m
Area of circle :
Thus, the area of this circle = 615.44 m²
Circumference of circle :
The circumference of this circle = 87.92 m
Therefore, the area of this circle = 615.44m² and the circumference of this circle = 87.92m
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Answer:
Step-by-step explanation:
GIVEN: A bag contain red marbles,
green marbles and
blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.
TO FIND: What is the probability both marbles are green.
SOLUTION:
Total marbles in bag
total number of green marbles
Probability that first marble will be green
Probability that second marble will be green
As both events are disjoint
probability both marbles are green
Hence the probability both marbles are green is
Let's call the two numbers and
.
Given these variables, we can say: , based on the first sentence in the problem.
Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:
To solve, we can simply substitute in for
in the second equation and solve.
- Set up
- Get terms on the left side to a common denominator for easier addition
- Simplify
- Cross multiplication (
)
- Simplify
- Subtract
from both sides of the equation
- Factor left side of the equation
- Zero Product Property
Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,
,
Since is not positive in this case,
is not a solution.
Thus, is our only solution. In this case,
,
which means that the smaller number is 14 and the larger number is 28.
Answer:
Step-by-step explanation:
To simplify the square roots, break the number under the square root into factors. Any factors which are perfect squares may be simplified to outside the square root.
and