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Nataly [62]
3 years ago
6

Can y’all do me a big big favor and help me pls

Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

it's either 3√36 or 2.002

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Point G lies between points F and H on FH.
dlinn [17]

Answer: x=3 ==> 1st option

Step-by-step explanation:

FH=FG+GH

18=4x+2x

6x=18

x=3 ==> 1st option

8 0
2 years ago
PLEASE HELP MATH
Novosadov [1.4K]
I believe C is your answer. 
I hope this helps!
7 0
3 years ago
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Which is greater 4/5 or 60%<br><br> i need help
Kisachek [45]

Answer:

4/5 is greater

Step-by-step explanation:

60% = 60/100

4/5 = 80/100

80>60

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3 years ago
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In a certain Algebra 2 class of 30 students, 18 of them play basketball and 9 of them
marshall27 [118]

Probability that a student will play both is 7/30

Step-by-step explanation:

Total students = 30

No. of students who play basketball = 18

Probability that a student will play basketball = 18/30

= 3/5

No. of students who play baseball = 9

Probability that a student will play baseball = 9/30

= 3/10

No. of students who play neither sport = 10

Probability that a student will play neither sport = 10/30

= 1/3

To find :

Probability that a student will play both = p(student will play both)

No.of students who play sport = 30 - 10

= 20

Out of 20 students 18 play basketball and 9 play baseball.

So, some students play both the sports.

No. of students who play both sports = 18 + 9 - 20

= 7

p(student will play both) = 7/30

Probability that a student will play both is 7/30

3 0
4 years ago
Simplify the problem: Sin theta Sec Theta
kherson [118]

Answer:

\tan \theta

Step-by-step explanation:

We have to simplify the following expression as given by

\sin \theta \times \sec \theta

= \frac{\sin \theta}{\cos \theta}

= \tan \theta ( Answer )

Because, we know that \sec \theta =\frac{1}{\cos \theta} and \tan \theta = \frac{\sin \theta}{\cos \theta}

If we consider \sin \theta = \frac{Perpendicular}{Hypotenuse} and \sec \theta = \frac{Hypotenuse}{Base},

then \sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta

3 0
3 years ago
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