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Nataly [62]
2 years ago
6

Can y’all do me a big big favor and help me pls

Mathematics
1 answer:
OverLord2011 [107]2 years ago
4 0

Answer:

it's either 3√36 or 2.002

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A=3 b=2 c=7<br>a+b+c=??<br>Help me please thank you​
tester [92]

Answer: 13

Step-by-step explanation:

<u>Given:</u>

a+b+c, where a=3, b=2, c=7

<u>Solve:</u>

Given

 a+b+c

Substitute values into the expression

=(3)+(2)+(7)

Combine like terms

=6+7

=13

3 0
3 years ago
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I need Help. I will give brainliest/
Len [333]

Answer:

the answer is 48.

there is no any answer to hundred

Step-by-step explanation:

we know that,

area of parellelogram=base×height

base=8cm,height=6cm

so, 8×6=48

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3 years ago
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General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}
mixer [17]

Answer:

\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

Step-by-step explanation:

Given:

\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1

First, note that

\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x

So, the equation is

-\cos x+\sin x= -1

Multiply this equation by \frac{\sqrt{2}}{2}:

-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}

The general solution is

x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

4 0
3 years ago
HELP DO IN A HOUR !!!
klemol [59]

Answer:

bro why did u take his points

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Step-by-step explanation:

5 0
3 years ago
BC=10, AC=x, and AB=2x-21. Solve for x ,and find the length of AB.
KonstantinChe [14]

Answer:

Briggs is planning to make abatch of home made play dough for an art projections

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