Performance would be the answer
Answer:
<u>VLANs</u>
Explanation:
Virtual LANs (VLANs) are a type of network connection or arrangement of network devices in the same broadcast domain. They are called Virtual LANs because they represent fractions or subgroups in the switch ports found in an Ethernet LAN.
Indeed, because of their topological arrangement, this reduces the security risk of unauthorized access to sensitive data or devices since the host can be placed on a different VLAN. Hence, in this scenario, using this network feature would allow visitors to plug into these ports to gain internet access, but they would not have access to any other devices on the private network.
A compiler, which has several parts, translates source code to executable code.
Answer:
The answer is "Option A".
Explanation:
The program to the given question can be given as:
program:
var1 = "Happy" #defining variable var1
var2= "Birthday" #defining variable var2
var3 = (var1+var2) *2 #defining variable var3 and calculate value
print (var3) #print value.
Output:
HappyBirthdayHappyBirthday
In the above python program, three variable is defined, that is var1, var2, and var3, in which variable var1 and var2 we assign a value, that is "Happy" and "Birthday".
In variable var3 we add the value of var1 and var2 variable and multiply by 2. It will print the variable value two times. and other options are not correct that can be defined as:
- In option B and C, Both variable var1 and var2 print there values two times but in option B var1 value print two time and var2 value print one time only and option C var1 variable value is print only one time and var2 variable value is print two times that's why it is not correct.
- In option C, Both variable var1 and var2 print there values two times that's why it is not correct.
Answer:
See Explaination
Explanation:
#include <iostream>
#include <string.h>
using namespace std;
char *mixem(char *s1, char *s2);
int main() {
cout << mixem("abc", "123") << endl;
cout << mixem("def", "456") << endl;
return 0;
}
char *mixem(char *s1, char *s2) {
char *result = new char[1 + strlen(s1) + strlen(s2)];
char *p1 = s1;
char *p2 = s2;
char *p = result;
while (*p1 || *p2) {
if (*p1) {
*p = *p1;
p1++;
p++;
}
if (*p2) {
*p = *p2;
p2++;
p++;
}
}
*p = '\0';
return result;
}
