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muminat
3 years ago
6

Which of the following galaxy types is most likely to be clearly identifiable, regardless of orientation? SBc

Computers and Technology
1 answer:
Reil [10]3 years ago
3 0

Answer:

The most likely galaxy type to be identifiable regardless of orientation is: Irr

Explanation:

The Irr galaxies don't have a discernable or usual shape; that is why it is relatively easy to identify.

When we talk about E type galaxies, this statement proves itself by the way the cumulus of stars compounds the galaxy. The elliptical galaxies have the form of ellipses, with a reasonable distribution of stars. The degree of eccentricity is the number that complements the E letter; that's why E0 galaxies are almost spherical, while E7 is considerably elongated.

SBc, SBa galaxies are spiral; this means it can be flat in some angles difficulting their identification process; in this case, the last letter means the way the arms display their form, with "c" having a vague form and "a" well-defined arms. That's why in some angles can be mistreated as another type of galaxy.

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Dahasolnce [82]

Cindy  can choose to exchange cyber threat information in the given scenario via the use of TAXII.

<h3>What is standardized protocol?</h3>

Standardized protocols is known to be the one that gives room for people or clients to communicate with any given window manager.

Note that in the above case, Cindy  can choose to exchange cyber threat information in the given scenario via the use of TAXII.

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8 0
2 years ago
In this exercise, you will create a couple of helper methods for ArrayLists in a class called ArrayListMethods.
nata0808 [166]

Answer:

package lab1;

import java.util.ArrayList;

import java.util.Iterator;

public class ArrayListMethodsTester

{

public static void main(String[] args)

{

ArrayList<String> stringArray = new ArrayList<String>();

stringArray.add("This");

stringArray.add("is");

stringArray.add("an");

stringArray.add("ArrayList");

stringArray.add("of");

stringArray.add("Strings");

System.out.println("Printing the arraylist:");

ArrayListMethods.print(stringArray);

System.out.println("\nArrayList is condensing:");

ArrayListMethods.condense(stringArray);

ArrayListMethods.print(stringArray);

System.out.println("\nArrayList is duplicating:");

ArrayListMethods.duplicate(stringArray);

ArrayListMethods.print(stringArray);

}

}

class ArrayListMethods

{

static void print(ArrayList stringArray)

{

  Iterator it = stringArray.iterator();

  while (it.hasNext())

     System.out.println(it.next() + " ");

     

}

static void condense(ArrayList stringArray)

{

  int length=stringArray.size();

     

  ArrayList cloneArray=(ArrayList) stringArray.clone();

     

  stringArray.clear();

  StringBuilder sb=new StringBuilder("");

     

  for (int i = 0; i < (length/2); i++)

  {

      sb.append(cloneArray.get(i));

      sb.append(" ");    

  }

  stringArray.add(sb);

     

  StringBuilder sb1=new StringBuilder("");

  for (int i = (length/2); i < length; i++)

  {

      sb1.append(cloneArray.get(i));

      sb1.append(" ");    

  }

  stringArray.add(sb1);

  }

static void duplicate(ArrayList stringArray)

{

  for (int i = 0; i < stringArray.size(); i+=2)

  {

      stringArray.add(i+1,stringArray.get(i));

  }

}

}

Explanation:

  • Get the length of the arraylist  to copy the array into another arraylist .
  • Empty the array so that new content can be stored in it .
  • Use a loop to half of array_list.
  • Use a loop from half of array_list to the end of arraylist and  append all into a single string.
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SpyIntel [72]

Answer:

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Explanation:

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Answer:

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Explanation:

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adoni [48]

Answer: wireframe

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It should be noted that the wireframe shows the arrangement or the page layout for the content of the website which includes the navigational systems and the interface elements and how they both combine to work together.

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