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soldier1979 [14.2K]
2 years ago
10

Assume a significance level of α=0.01 and use the given information to complete parts​ (a) and​ (b) below. Original​ claim: The

mean pulse rate​ (in beats per​ minute) of a certain group of adult males is 75 bpm. The hypothesis test results in a​ P-value of 0.0087. a. State a conclusion about the null hypothesis.​ (Reject H0 or fail to reject H0.) Choose the correct answer below. A. Reject H0 because the​ P-value is less than or equal to α. B. Fail to reject H0 because the​ P-value is less than or equal to α. C. Fail to reject H0 because the​ P-value is greater than α. D. Reject H0 because the​ P-value is greater than α.
Mathematics
1 answer:
mario62 [17]2 years ago
6 0

Answer:

A. Reject H0 because the​ P-value is less than or equal to α.

Step-by-step explanation:

Decision:

If the pvalue of the test is less than the significance level, we reject the null hypothesis H0.

Otherwise, we fail to reject the null hypothesis H0.

In this question:

Significance level: 0.01

P-value: 0.0087

0.0087 < 0.01, so we reject H0.

The correct answer is given by option A.

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Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

(b) In the table of the first attachment, the column headed by g(x) gives iterations of Newton's Method. (For Newton's method, it is convenient to let the calculator's derivative function compute the derivative f'(x) of the function f(x). We have defined g(x) = x - f(x)/f'(x).) The result of the 3rd iteration is ...

... x ≈ 3.0473167

(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

... x ≈ 3.2291234

(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

... x ≈ 3.0477377

(e) Using <em>Mathematica</em>, the roots are found to be as shown in the second attachment. The highest root is about ...

... x ≈ 3.0466805180

_____

<em>Comment on these methods</em>

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

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2 years ago
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r-ruslan [8.4K]

Answer:

too much

Step-by-step explanation:

8 0
2 years ago
Two intelligent, honest students are sitting together at lunch one day when their math teacher hands them each a card. “your car
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Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
4     3
5     3
6     2
6     3
9     2
12  1
15  1
18  1

Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
6     2
6     3

Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.

2     6
3     6

Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
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HELP WILL GIVE BRANLIEST!
Alecsey [184]

Answer:

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Step-by-step explanation:

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3 years ago
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The answer for this question is 4.
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