F(k) = -1/2k + 6
You can get this by solving for J and then using f(k) in its place.
Answer:
D. It is on the angle bisector of ∠BAC
Step-by-step explanation:
Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.
Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.
Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.
Step-by-step explanation:
Aw poor thing :(. I'm so sorry, honey. Is there anything I can do? If you need to vent or talk about it you're always welcome to talk to me. I haven't seen my friends since March so I understand. If there is anything that I can do I will gladly do it if possible. Stay safe ❤️.
Hello,
a)
the gradient is the slope:
y+2=3(x-0) or y=3x-2
b) slope is -5 (parallele to y=-5x+4)
y+1=-5(x-0) or y=-5x-1
