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m_a_m_a [10]
2 years ago
8

!!!! Help please whoever evaluates it I’ll give you Brainly

Mathematics
1 answer:
bonufazy [111]2 years ago
8 0

Answer:

733

Step-by-step explanation:

3*3 =9

3*3=9

3*3=9

9*9= 81*9= 729+4 = 733

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Is Water is stored in response to changing demand a cause or effect
True [87]

the answer is effect

7 0
2 years ago
Read 2 more answers
PLEASE HELP
mylen [45]

Answer:

3

Step-by-step explanation:

Function B  looks like   y = 3x + 4

with Function A being y = 9x + 4

9 is 3 times more than 3

6 0
3 years ago
Van purchased a DVD player on sale. The original selling price was
hammer [34]

Answer:

the first step is find the amount of money you saved

Step-by-step explanation:

171.50-145.12=26.38

26.38 / 171.5 = .154

15.4%

8 0
2 years ago
The weight of mr nazeer is 7 times that of his son. What's the ratio of their weights?
Mekhanik [1.2K]

Answer:

<h3>7:1</h3>

Step-by-step explanation:

Let the weight of mr nazeer be x

Let the weight of his son be y

If the weight of mr nazeer is 7 times that of his son, then x = 7y

To get the ratio of their weight:

Ratio = weight of father/weight of son

Ratio = 7y/y

Ratio = 7/1

Ratio = 7:1

Hence the ratio of their weights is 7:1

3 0
3 years ago
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
3 years ago
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