The absolute value of a number cannot be an negative constant, thus there is no solution too the given problem.
Answer:
12
Step-by-step explanation:
a = 2
b = 3
c = 9
a(c - b)
2(9 - 3)
2(6)
12
R + w = 50
r = 6w + 1
now we sub ..
6w + 1 + w = 50
7w + 1 = 50
7w = 50 - 1
7w = 49
w = 49/7
w = 7 <== white beads
r = 6w + 1
r = 6(7) + 1
r = 42 + 1
r = 43 <=== red beads
This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.
