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sweet [91]
2 years ago
13

im basically just gonna keep putting up sum1 hmu till sum1 with an interesting conversation talks 2 me l-m-a-oooooo

Mathematics
1 answer:
yawa3891 [41]2 years ago
3 0

Answer:

<h2><u><em>My discord server is very close to 100 members</em></u></h2><h2><u><em>the code is: qSnYEsP</em></u></h2><h2><u><em>please join it :)</em></u></h2><h2><u><em>Or you can copy my name and paste it into the discord join server thing</em></u></h2><h2><u><em>both works</em></u></h2>

Step-by-step explanation:

You might be interested in
what is the equation of the line in point slope form that goes through (-2,-1) and is perpendicular to y=5x+3?
stich3 [128]
Point slope form is y-y1=m(x-x1)

Since we have to write the equation of a perpendicular line we will have to use the slope that is opposite and reciprocal.

y - (-1) = - \frac{1}{5} (x - (-2))
y + 1 = - \frac{1}{5} (x + 2)

Hope this helps :)
8 0
3 years ago
Calculate the density of a rock that has a mass of 454 g and a volume of 100.0 cm3.
Katena32 [7]

Answer:

4.54 g/cm^3

Step-by-step explanation:

d = m/v

d = 454 g ÷ 100.0 cm^3

d = 4.54 g/cm^3

3 sig figs so this answer is complete

6 0
3 years ago
17−5r+9r=12+6r−1<br> what is r?
jonny [76]

Answer:

r=3

Step-by-step explanation:

simplify each side

4r+17=6r+11

Subtract 4r from both sides.

17=2r+11

Subtract 11 from both sides

6=2r

divide both sides by 2

3=r

7 0
3 years ago
Travis eats 28 cookies in 4 weeks, Eating the same number of cookies each week. Dylan eats 24 cookies in three weeks, eating the
dlinn [17]

Answer:

Travis needs to slow down

Step-by-step explanation:

Stop eating cookies, Travis.

5 0
3 years ago
In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
Mademuasel [1]

Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

And, ∠ PAB ≅ ∠ PBA

∠DPC ≅ ∠ APB ( reflexive)

Therefore, By AAA similarity postulate,

\triangle PDC \sim \triangle PAB

Thus, By the definition of similarity,

\frac{PD}{PA} = \frac{DC}{AB}

\frac{PD}{PD+3} = \frac{11}{18} ( because PA = PD+DA)

⇒ 18 PD = 11 PD +33

⇒7PD = 33

⇒ PD = 33/7

Again by the definition of similarity,

\frac{PC}{PB} = \frac{DC}{AB}

\frac{PC}{PC+7} = \frac{11}{18} ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA =  PD+DA = 33/7 + 3 = 7\frac{5}{7}

And, PB = PC + CB = 11 + 7 = 18


8 0
3 years ago
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