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steposvetlana [31]
3 years ago
9

Plz help! I will do anything

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0
It’s b if i’m not mistaken
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Solve: y= -5<br> x= y + 3<br>what is the pair (_,_)
olga nikolaevna [1]
We are given y=-5.  Substituting, x=y+3=-5+3=-2.

Thus, our ordered pair (x, y) is (-2, -5).
8 0
3 years ago
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Will mark Brainlest hellpppp​
Anna007 [38]

h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

h(2) =  \frac{2 {(4)}  - 2 + 1}{6 - 2}

h(2) =  \frac{ 8  - 1}{4}

h(2) =  \frac{7}{4}

h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

5 0
3 years ago
A. a scientist is studying the change in population for two species of fish in a lake. The table shows how the numbers of each s
Rom4ik [11]

Answer:

The data can be modeled using linear equatins, because there's the same amount of population for fish A (+20 per year) and fish B (+30 per year) every year.

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A piece of cable 8.5 long weighs 52 grams. What will a 10-Cm length of the same cable weigh?
mars1129 [50]
Ratio and proportion 8.5 cm/52 grams= 10 cm/x grams cross multiply 8.5x=520 x= 61.18 grams hope this helps
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a. po yung answer

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