PLS PLS HELP ME NO LINKS IF YOU GIVE ME RIGHT I WILL GIVE BRAINLIEST 50 POINTS!!!!!!!!!

Yuri [45]

Five times a number less than one hundred.

6 0

3 years ago

A jar contains 10 marbles marked with the numbers 1 through 10. You pick a marble at random. What is the probability of not pick

mr_godi [17]

Answer:

9/10

Step-by-step explanation:

Since there is only one marble per number and there is only one marble for the number 8 you would take just subtract 10-1 which would give you 9.

5 0

3 years ago

Which is bigger 2/5 or 4/9

Jlenok [28]

The easiest way to solve this comparison without any unusual comparisons is to find a common denominator for the two fractions.

2/5 = 18/45
4/9 = 20/45

Since 20/45 is bigger than 18/45, we know that 4/9 is greater than 2/5

6 0

3 years ago

Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

5 0

3 years ago

2.

Jet001 [13]

Answer:

119.2

Step-by-step explanation:

Given the following :

Mean (m) = 100 years

Standard deviation (sd) = 15 years

closest to the age of a Galápagos Islands giant tortoise at the 90th percentile of the

distribution?

Obtain the Zscore for 90th percentile (0.90) on the z table = 1.28

Zscore = (X - mean) / standard deviation

1.28 = (X - 100) / 15

1.28 × 15 = X - 100

19.2 = X - 100

19.2 + 100 = X

X = 119.2

3 0

3 years ago