A pattern of growth<span> in which, in a new environment, the </span>population<span> density of an organism increases slowly initially, in a positive acceleration phase; then increases rapidly, approaching an exponential </span>growth<span> rate</span>
6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°
Mowing 4 lawns in 6 hours gives a mowing rate of 6/4 = 1.5 hours per lawn.
To mow 9 lawns, you need 1.5*9 = 13.5 hours.
The answer is B.
Item | Frequency
0 | 2
1 | 5
2 | 4
3 | 3
5 | 1
Hope I helped!
Answer:
Make an eqaution from here.
Let’s make evening 2 “x”
So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).
X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x
And when solved, it has to equal 105.
So solve from here.
Combine like terms.
6x-9=105
Isolate
6x=114
x= 19
First evening is 9 less then 19, so 10.
The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76
1st night = 10
2nd night= 19 calls
Thrid night= 76 calls
