The incorrect rounding for 53.864 is 53.87
<h3>How to approximation a decimal?</h3>
The decimal to be approximated is as follows;
53.864
The first option rounded the decimal to 2 significant figures or a whole number.
The second option is incorrect because they rounded it wrongly to 2 decimal places. The correct 2 decimal round is 53.86.
The third option is approximated rightly to one decimal place.
The last option is rounded to the closes tens term.
learn more on approximation here: brainly.com/question/9608644
#SPJ1
Answer:
Step-by-step explanation: Not too sure how to explain it this is how you simplify it pretty sure
2x-y=7
+2x +2x add to both sides to get y alone because it has no friends
___________
-y=7+2x get rid of the negative on the y value
__________
y= -2x -7
Answer: 3x^2 - 3
Step by step explanation:
Answer:
Step-by-step explanation:
From the question we are told that
Ratio 6:9:15
Total amount to e shared N=£5940
Generally the Ratio can divide the Total amount mathematically as follows
Ratio
6:9:15/3=2:3:5
Sum of ratio
2+3+5=10
For Aaron
For Beth
For Charlie
Check answer
Answer:
Step-by-step explanation:
a+b+c=0, a+b=-c,a+c=-b, b+c=-a
(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=
a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=
a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=
a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=
a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=
6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=
2*[3abc-(a^3+b^3+c^3)]=0
so 3abc-(a^3+b^3+c^3)=0
so a^3+b^3+c^3=3abc
