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leva [86]
3 years ago
9

What is 39.51 rounded to the nearest second

Mathematics
1 answer:
pogonyaev3 years ago
8 0
36 is the answer ( i hope)
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to enter the fair and $12 on food. Rides at the fair cost $1.25 per ride. Which function can be used to determine how much money
Nana76 [90]
F(x) = 1.25x + 12.

12 Is the cost of food, and 1.25x represents that every ride (x) is 1.25 dollars.

f(1) = 1.25(1) + 12
f(1) 13.25

If he rides one ride, then it will cost this 13.25 dollars in total

f(2) = 1.25(2) + 12
f(2) = 14.5

If he rides two rides, then it will cost 14.5 dollars in total

f(3) = 1.25(3) + 12
f(3) = 15.75

If he rides 3 rides, it will cost 15.75 dollars in total, etc. etc.

Hope this helps!!
4 0
3 years ago
How much money will you have if you started with $ 50, and put it in an account that earned 9.7% every year for 15 years?
Zielflug [23.3K]
Compound interest:
A=p(1+\frac{r}{100})^{n}
<span>A=50(1+\frac{9.7}{100})^{15}
</span>A=50(1.097)^{15}
A=50*4.00958
A= <span>$200.48</span>
3 0
3 years ago
Solve for x. 5(x – 10) = 30 – 15x
klio [65]
You can start by distributing the 5 to everything in the parenthesis.
5x-50=30-15x

Then get rid of your x values from one side, I chose to subtract 5x

-50 = 30 - 20x

Then subtract 30

-80=-20x
/-20
4=x

You can check by plugging your x into the equation to make sure it's right!

6 0
3 years ago
Please whats the answer to this question
Shkiper50 [21]
I believe it’s 800 cm^3
4 0
3 years ago
Read 2 more answers
Look at the picture<br>​
Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
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