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3 years ago

9. A home improvement store advertises 60 square

Mathematics

2 answers:

vlada-n [284]3 years ago

7 0

Answer:

C. $5.55

Step-by-step explanation:

Total cost of installing 60 square feet of flooring

= $253.00 + $80

= $333

Total number of square feet for flooring = 60

Now cost per square foot of the flooring

= total cost/total number of square feet

That’s

$333/60 = $5.55

Each square foot cost $5.55

svlad2 [7]3 years ago

7 0

Each square foot cost $5.55 so that would be answer C

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Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

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3 years ago

Which of the following relations describes a function?

grin007 [14]

It’s c because none of the c values repeat

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3 years ago

Negation of no planes have three wheels

anygoal [31]

Ohyeah free points bruhoo

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3 years ago

Chris took a vacation trip to maine, where sales tax on taxable items is 5%. in maine, prepared food and lodging are taxed an ad

12345 [234]

So, it's just an annoying problem. Keep the tax rates in mind for each thing.
$70 of souvenirs mean the tax is 5% since it is not prepared food, lodging, or auto rentals.
$580 on prepared food means that has 7% tax because it is special.
$620 on the car has a 10% tax, as stated in the problem.
So do 70(1.05)+580(1.07)+620(1.1) to get $1376.1.0

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3 years ago

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Please solve these asap. 50 points and will be marked as brainliest

Sergeu [11.5K]

Answer:

Hi myself Shrushtee.

Step-by-step explanation:

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3 years ago