What is the length of a diagonal are on your answer sheet write the letter only of the correct answer choice

Mathematics

1 answer:

fgiga [73]3 years ago

6 0

Answer:

the correct answer is option C

You might be interested in

Consider the circle of radius 5 centered at (0,0), how do you find an equation of the line tangent to the circle at the point (3

Flauer [41]

$\text{We know that the tangent at any point on a circle is perpendicular}\\
\text{to the radius at that point.}\\
\\
\text{so first we find the equation of the line joining (0,0) and (3,4)}\\
\text{and then using the slope, we find the line perperndicular to it at (3,4)}\\
\\
\text{the equation of the line passing through (0,0) and (3,4) is}\\
\\
y-0=\frac{4-0}{3-0}(x-0)$

$\Rightarrow y=\frac{4}{3}x\\
\\
\text{so the slope of radius is }m=\frac{4}{3}.\\
\\
\text{we know that the product of the perpendicular lines is }-1. \\
\\
\text{so the slope of the perpendicular line would be}=-\frac{1}{4/3}=-\frac{3}{4}\\
\\
\text{So the equation of the tangent line has slope }-\frac{3}{4} \text{ and}\\
\text{passing through (3,4). so equation of tangent line is}$

$y-4=-\frac{3}{4}(x-3)\\
\\
\Rightarrow y-4=-\frac{3}{4}x+\frac{9}{4}\\
\\
\Rightarrow y=-\frac{3}{4}x+\frac{9}{4}+4\\
\\
\Rightarrow y=-\frac{3}{4}x+\frac{9+16}{4}\\
\\
\text{so the equation of tangent line is:} y=-\frac{3}{4}x+\frac{25}{4}$

5 0

4 years ago

Will give brainliest to first correct answer! find missing length indicated

Reptile [31]

Answer:

Where's the question? Lol

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write a linear function f with the values f(-4) = 0 and f(0) =0 please help

Sergeeva-Olga [200]

$f(\stackrel{x_1}{-4})=\stackrel{y_1}{0}\qquad f(\stackrel{x_2}{0})=\stackrel{y_2}{0}~\hfill (\stackrel{x_1}{-4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-4)}}}\implies \cfrac{0}{0+4}\implies \cfrac{0}{4}\implies 0$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{0}(x-\stackrel{x_1}{(-4)})\implies \boxed{y = 0}$

6 0

3 years ago

Need help my teacher is going to be really mad

neonofarm [45]

This is how I figure these type of questions out you can draw a circle on the J,K,L the trace it to make a triangle it should be less then 90 degrees if not then you might’ve traced it wrong.

5 0

4 years ago

Find the length of the line joining the points A(-2,10) and B(-8,2)

Vesnalui [34]

Length of the line

= $\sqrt{((-2)-(-8))^{2}+(10-2)^{2} }$