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skad [1K]
3 years ago
10

​ A loggerhead sea turtle decided to swim to grab some lunch! She swam 4 miles west and 3 miles south until she stopped and foun

d a delicious crab to eat. What is the distance between the sea turtle's start point and where she found the crab? Round to the nearest tenths place, if necessary
a
19 mi

b
7 mi

c
5 mi
Mathematics
1 answer:
Alja [10]3 years ago
6 0

Answer:

Down below.

Step-by-step explanation:

Use Pythagorean’s Theron

9 + 16 = c squared

25 = c squared

c = 5

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A basket contains 12 apples and some other fruit. Write an equation that could be used to find the total number of fruits in the
o-na [289]
A basket contains 12 apples and some other fruit
40% of the total fruit are apples...so 40% of the total fruit is 12..

0.40x = 12....with x being the total fruit in the basket <== ur equation
x = 12 / 0.40
x = 30....and u have 30 pieces of fruit in the basket
7 0
3 years ago
I need help with number 5
Tju [1.3M]

Answer:

B. BD = 9

Step-by-step explanation:

Simply set the 2 equations equal to each other (both are congruent due to perpendicular bisector):

6x + 3 = 3x = 6

3x + 3 = 6

3x = 3

x = 1

Then substitute 1 for <em>x</em> in BD

6(1) + 3

6 + 3

BD = 9

7 0
3 years ago
Read 2 more answers
A triangle has three different integer side lengths and a perimeter of 20 units. What is the max length of any one side?
Troyanec [42]
X + x+1 + x + 2 = 20
3x + 3 = 20
3x = 17 but can't start with x = 6 because 6+7+8 > 20,
so have start with 5 + 6 + 7 = 18 are the 3 sides.
3 0
3 years ago
X = ? Degrees<br><br> Y= ? Degrees
Dmitry_Shevchenko [17]

Answer:

X = i don't know

Y = 50°

Step-by-step explanation:

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8 0
3 years ago
Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

⇒ \frac{15}{Sin 29} = \frac{20}{sin B}

Using value of sin 29°

⇒ \frac{15}{0.49} = \frac{20}{sin B}

Cross multiplying both side.

⇒ Sin B= \frac{20\times 0.49}{15} = 0.65

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ 29+41+B= 180

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

7 0
3 years ago
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