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3 years ago

Answer the following Question with Appropriate Explanation

Mathematics

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

option is B)

Step-by-step explanation:

2x is a perfect square. but x is not a perfect square, this brings us to the conclusion tht prob x is 2.

2x = 4

hence correct option is B) 4x is a perfect square, as 4x4=16, which is a perfect square...

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The bottom one says 9/2 so please help with these questions, I have more on my profile.

eimsori [14]

18. Solve for x by factoring diamond method

10x^2 - 29x - 21 = 0 becomes

(2x - 7)(5x + 3) = 0

x = 7/2, -3/5

19. To model this we will do

(x + 9)(x + 9) = 169

distribute

x^2 + 18x - 88 = 0

factor

(x - 4)(x + 22) = 0

The length is 4m

20. This can be modeled by

(l)(l +5) = 234

distribute

l^2 + 5l -234 = 0

factor

(l-13)(l+18) = 0

The length is 13

The width is 18

21. To find this you divide the x term by 2 and square it so

10/2 = 5

5^2

22. To find this you divide the x term by 2 and square it so

9/2 = 4.5

4.5^2

81/4

7 0

3 years ago

Please help me with this math problem. I have to Use the quadratic formula to solve each equation.

Ierofanga [76]

You have to solve the given expression for q:

$2q^2-8=3q$

This expression has a quadratic term, which means that it is a quadratic equation. To find the value or values of q, you have to use the quadratic equation, using "q" as the variable instead of "x"

$q=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

a is the coefficient of the quadratic term

b is the coefficient of the q term

c is the constant

- First, zero the equation by passing 3q to the left side of the equal sign:

$\begin{gathered} 2q^2-8=3q \\ 2q^2-8-3q=3q-3q \\ 2q^2-3q-8=0 \end{gathered}$

For this equation the coefficients are:

a= 2

b= -3

c= -8

Replace them in the formula and solve:

$\begin{gathered} q=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ q=\frac{-(-3)\pm\sqrt{(-3)^2-4*2*(-8)}}{2*2} \\ q=\frac{3\pm\sqrt{9+64}}{4} \\ q=\frac{3\pm\sqrt{73}}{4} \end{gathered}$

Next, to determine each possible value of q, you have to solve the sum and difference separately:

Sum