Answer:
Yes they are correct
Step-by-step explanation:
Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.
<h3>What centers of distribution should be used?</h3>
The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.
The data is said to be symmetric when the mean and median are equal or very close.
Bakery A mean:
= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8
= 49
Bakery A median is 49.5
Bakery B mean:
= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8
= 39.5
Bakery B median is 44.
This shows that Bakery A data is symmetric so the best center of distribution to use is mean.
Bakery B is not symmetric so the center of distribution to use is median.
Find out more on symmetric data at brainly.com/question/7130507
#SPJ1
The sample std. dev. will be (14 inches) / sqrt(49), or (14 inches) / 7, or 2 inches.
Find the z score for 93.8 inches:
93.8 inches - 91.0 inches 2.8 inches
z = ------------------------------------- = ----------------- = 1.4
2 inches 2 inches
Now find the area under the standard normal curve to the left of z = +1.4.
My calculator returns the following:
normalcdf(-100,1.4) = 0.919. This is the probability that the mean annual precipitation during those 49 years will be less than 93.8 inches.
Answer:
it belongs to rational number......
Answer:
The question is kinda funny. I think the graph isn't correct cos a and b coordinate ain't right
