I'd be able to figure this out if I could see the graph.
V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)
(dv/dt)*(dt/dh) = dv/dh
dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)
5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)
then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))
He can complete about 6 pages of math homework.
you first do 200 divided by 32 and you get 6.25. So therefore Dan can complete 6 pages in 200 minutes.
Answer:
71°
Step-by-step explanation:
The angle of elevation of the hill can be obtiaed using trigonometry :
Given
the opposite length = 14.5 feets
Adjacent = 5 feets
The angle of elevation vabnbe obtained using :
Tan θ = opposite / Adjacent
Where θ = angle of elevation
Tan θ = 14.5 / 5
Tan θ = 2.9
θ = tan^-1(2.9)
θ = 70.97 = 71°
