I really, really don't like this question. People have preferences in solving quadratics. I would personally use, and would encourage anyone to use the quadratic equation. That's because completing the square would get excessively fractional, graphically doesn't even work because the solutions are imaginary, and differentiating it wouldn't be necessary, as there are no irrational numbers (except i, which is just imaginary). So, in short, quadratic equation because you can't get anything graphically, the answers are ugly fractions, and you can actually use that method.
Answer:
Options (C), (D) and (E)
Step-by-step explanation:
Slope of the given line = 
Any line having same slope will be parallel to the given line otherwise the lines will intersect.
Therefore, we will find the slope of the lines passing through two points given in the options.
Option A
Slope of the line passing through (12, -13) and (15, -12)
m = 
= 
=
Therefore, both the lines are parallel having no point of intersection.
Option B
Slope = 
=
Both the lines are parallel having no point of intersection.
Option C
Slope = 
= 
Therefore, both the lines will intersect.
Option D
Slope = 
= 
Both the lines will intersect each other.
Option E
Slope = 
=
Both the lines will intersect each other at a point.
Options (C), (D) and (E) are the correct options.
Answer:
561
Step-by-step explanation:
an = dn - (a-d)
The difference is 3.
The first term is 12.
an = 3n - (12-3)
an = 3n - 9
Put n as 1, 2, 3, 4, 5 ....22.
3(1) - 9 = -6
3(2) - 9 = -3
3(3) - 9 = 0
3(4) - 9 = 3
3(5) - 9 = 6
...
3(22) - 9 = 57
Add the first 22 terms.
-6+-3+0+3+6+9+12+15+18+21+24+27+30+33+36+39+42+45+48+51+54+57
= 561
Answer:
y= -x+8
Step-by-step explanation:
slope int. form: y=mx+b
first, we need to find the slope (m)
the two points are (2,4) and (7,-1).
to find the slope we do (y2-y1)/(x2-x1)
doing this we get -5/5=-1
now we can plug in point (2,4) and the slope into y=mx+b
doing this we get:
4=-1(2)+b
4=-2+b
b=8
now we have the equation:
y= -x+8
1+4=5
2+5=7
3+6=9
8+11=19
hope this helped:)
