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adell [148]
3 years ago
5

Last month , Luke and Stefen sold candy to raise money for their debate team . Stefen sold 1/5 as much candy as Luke did . If Lu

ke sold 3/4 of a box of candy, how many boxes of candy did Stefan sell?​
Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

3/20

Step-by-step explanation:

stefan sell 1/5 × 3/4 = 3/20 boxes of candy

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What IS the slope of a line that is perpendicular to the line y= --x + 5?
Black_prince [1.1K]
<h3>Slopes of perpendicular lines.</h3>

Let k: y = a₁x + b₁ and l: y = a₂x + b₂. Then

<h3>k ║ l ⇔ a₁ = a₂</h3><h3>k ⊥ l ⇔ a₁ · a₂ = -1</h3>

We have the line y = -x + 5 ⇒ a₁ = -1.

Therefore

a₂ · (-1) = -1

-a₂ = -1     I<em>change the signs</em>

<h2>a₂ = 1</h2>
3 0
2 years ago
I HAVE TO SUBMIT NOW PLS HELP
Anettt [7]

Answer:

391 feet

Step-by-step explanation:

6 0
3 years ago
Please help and thanks​
Tanya [424]

Answer:

50

Step-by-step explanation:

Assuming you're solving for Q, the first step is to multiply the first set of parenthesis by 0.10:

0.10(72-Q) = 7.2 - 0.1Q

The next step is to combine the terms that have Q in them:

7.2 - 0.1Q + 0.25Q = 14.7

7.2 + 0.15Q = 14.7

Now isolate 0.15Q:

0.15Q = 14.7 - 7.2

0.15Q = 7.5

Divide 7.5 by 0.15 to solve for Q:

Q = 7.5/0.15 = 50

4 0
2 years ago
An online polling site posed this question: "How much stock do you put in long-range weather forecasts?" Among its Web site user
borishaifa [10]

Answer:

(a) 1155.84

(b) 48.2%

(c) D

Step-by-step explanation:

The number of total responses is, <em>N</em> = 38,528.

(a)

It is provided that 3% answered with "a lot".

Compute the actual number of responses consisting of "a lot" as follows:

n (a lot) = N × P (a lot)

            = 38528 × 0.03

            = 1155.84

Thus, the actual number of responses consisting of "a lot" is 1155.84.

(b)

The number of responses consisting of "very little or none" is,

n (very little or none) = 18,566

Compute the percentage of responses consisted of "very little or none" as follows:

P(\text{very little or none})=\frac{n(\text{very little or none})}{N}

                                  =\frac{18566}{38528}\\\\=0.481883\\\\\approx 0.482

The percentage is: 0.482 × 100% = 48.2%.

Thus, the percentage of responses consisted of "very little or none" is 48.2%.

(c)

As the sample size increases the sample statistic value gets closer and closer to the actual population parameter value.

Thus, making the sample statistic an unbiased estimator of the population parameter.

And proving that the sample is a true representative of the population.

Thus, the correct option is (D).

7 0
3 years ago
Can someone understand did right,how i graph it whats my m and b etc. quiz tomorrow
LiRa [457]
M is the slope amount (the number with the x variable) and if not already put into a fraction, then it is x over one.
b is the beginning number, this number gets put on the y axis first.
be sure to do b before anything else.
3 0
4 years ago
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