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3 years ago

Angles 3, 4, and 5 make a triangle. what is the sum of their angles? *

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

180 I believe because all angles in a triangles will ALWAYS add up to 180

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1.) What is the slope of the line perpendicular to a line with the slope of<br> 2/3?

daser333 [38]

Answer:

-3/2

Explanation:

Slopes of perpendicular lines are opposite reciprocals, which means you flip them and switch them from positive to negative, or the other way around.

8 0

3 years ago

PLS I NEED HELP WITH MY EXAM

Neporo4naja [7]

Answer:

F. a1 = –5, an = 5an-1

Step-by-step explanation:

a1 = -5 <---- Answer

r = -25/-5 = 5

an = r(an - 1)

an = 5(an - 1) <---- Answer

Hope this helps!

5 0

3 years ago

Read 2 more answers

Let f(x) =[[x]], what is f(-5.2)

ANEK [815]

flooring a value, simply means, dropping it to the closest integer, so for the floor function or ⌊x⌋, that means

⌊ 2.5 ⌋ = 2

⌊ 2.00000001 ⌋ = 2

⌊ 2.999999999999⌋ = 2

⌊ -2.0000000001⌋ = -3

⌊ -2.999999999999⌋ = -3

let's recall that on the negative side of the number line, the farther from 0, the smaller, so -1,000,000 is a tiny number compared to the much larger -1.

⌊ -5.2 ⌋ = -6.

5 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$