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Monica [59]
2 years ago
6

3x − 2y = 18 y = 2x − 13

Mathematics
2 answers:
Mamont248 [21]2 years ago
6 0

I'm guessing you want x and y solved.

Answer: x=10 and y=6

Explanation:

For X: Substitute the y-equation (y-2x-13) into the first equation (3x-2y=18) so your equation is 3x-2(2x-13)=18. Do the distribution property and the equation will be 3x-4x+26=18. Put like terms on the same side of the equal sign and combine like terms (subtract 26 on both sides) and the equation will be -x = -10. To make x positive, make both sides positive and you get x=10.

For Y: Substitute your x answer (10) into the first equation (3x-2y=18) and you will get 30-2y=18. Subtract 30 from both sides and you get -2y=12. Divide both sides by the common factor of -2 and you get y=6.

jenyasd209 [6]2 years ago
3 0

Answer:

x = - 8

3x - 2y = 18 is the same as 3x - (2x - 13 times 2) = 18

Then I used an algebra site for the rest.

It should be x = - 8

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ZN
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Given tangent, ZN, to the circle and the arc \widehat{ZMB} = 280°, we have that

the angle formed by the chord BZ and the tangent ZN, ∠BZN is 50°

<h3>Which method can be used to find ∠BZN?</h3>

The given parameters are;

A tangent to the circle O = ZN

m \widehat{ZMB}} = \mathbf{280^{\circ}}

Required:

Angle ∠BZN

Solution;

Please find attached the drawing of the circle and tangent

From the drawing, we have;

∠BOZ = 360° - 280° = 80°

ΔBOZ is an isosceles triangle, which gives;

∠BZO = ∠ZBO

\angle BZO = \dfrac{(180^{\circ}- 80^{\circ}) }{2} = \mathbf{50^{\circ}}

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∠OZN = ∠BZO + ∠BZN

∠BZN = ∠OZN - ∠BZO

Which gives;

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  • The measure of angle ∠BZN =<u> 50°</u>

Learn more about tangents to a circle here:

brainly.com/question/14561226

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