Choose the fraction that has not been reduced to simplest form.
1 answer:
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Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,
where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)
Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)
Hence the thickness difference should be
Answer:
Option D
Step-by-step explanation:
f(x) =
Transformed form of the function 'f' is 'g'.
g(x) =
Property of vertical stretch or compression of a function,
k(x) = x
Transformed function → m(x) = kx
Here, k = scale factor
1). If k > 1, function is vertically stretched.
2). If 0 < k < 1, function is vertically compressed.
From the given functions, k =
Since, k is between 0 and , function f(x) is vertically compressed by a scale factor
.
g(x) = f(x + 4) represents a shift of function 'f' by 4 units left.
g(x) = f(x - 4) represents a shift of function 'f' by 4 units right.
g(x) =
Therefore, function f(x) has been shifted by 4 units left to form image function g(x).
Option D is the answer.
The complete question in the attached figures
we know that
1 ft---------------> 0.083333 in
so
<span>24 inches high--------------> 24*0.083333=2 ft
</span><span>36 inches wide--------------> 36*0.083333=3 ft
</span><span>we will analyze each drawing
</span><span>
drawing a) scale 1/4 in/ 1 ft ----------> (1/4)/1=1/4
for a high of 2 ft-------------> 2*(1/4)=0.5 in
f</span>or a wide of 3 ft-------------> 3*(1/4)=0.75 in
drawing a) is not solution
drawing b) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing b) is not solution
drawing c) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing c) is not solution
drawing d) scale 1 in/ 1 ft ----------> (1)/1=1
for a high of 2 ft-------------> 2*(1)=2 in
for a wide of 3 ft-------------> 3*(1)=3 in
drawing d) is a solution
the answer is
The correct model of the flag is the drawing D
we know that
1 ft---------------> 0.083333 in
so
<span>24 inches high--------------> 24*0.083333=2 ft
</span><span>36 inches wide--------------> 36*0.083333=3 ft
</span><span>we will analyze each drawing
</span><span>
drawing a) scale 1/4 in/ 1 ft ----------> (1/4)/1=1/4
for a high of 2 ft-------------> 2*(1/4)=0.5 in
f</span>or a wide of 3 ft-------------> 3*(1/4)=0.75 in
drawing a) is not solution
drawing b) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing b) is not solution
drawing c) scale 1/2 in/ 1 ft ----------> (1/2)/1=1/2
for a high of 2 ft-------------> 2*(1/2)=1 in
for a wide of 3 ft-------------> 3*(1/2)=1.5 in
drawing c) is not solution
drawing d) scale 1 in/ 1 ft ----------> (1)/1=1
for a high of 2 ft-------------> 2*(1)=2 in
for a wide of 3 ft-------------> 3*(1)=3 in
drawing d) is a solution
the answer is
The correct model of the flag is the drawing D