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2 years ago

Find the are of the trapizoind

Mathematics

1 answer:

Andreyy892 years ago

6 0

9514 1404 393

Answer:

7.5 square units

Step-by-step explanation:

The formula for the area of a trapezoid is ...

A = 1/2(b1 +b2)h

where b1 and b2 are the lengths of the parallel bases, and h is the perpendicular distance between them.

Here, the bases are TR = 1 and PA = 4. The height is 3 units, so the area is ...

A = (1/2)(1 +4)(3) = 15/2 = 7.5 . . . . square units

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Afina-wow [57]

Answer:

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Step-by-step explanation:

65x+40y=765

65(5)+40(11)=765

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2 years ago

The midpoint of a line can be found using either a compass and straightedge construction or a straightedge and tracing paper con

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2 years ago

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Eight less a number is less than or equal to 17

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Step-by-step explanation:

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3 years ago

A pole that is 3.1m tall casts a shadow that is 1.29m long. At the same time, a nearby building casts a shadow that is 44.75m lo

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3 years ago

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The supplement of an angle is 50 less than 3 times its complement, find the measure of the angle

Lelechka [254]

Answer:

$20^{\circ}$ .

Step-by-step explanation:

Two angles are supplements of one another if their sum is $180^{\circ}$ .

Two angles are complements of one another if their sum is $90^{\circ}$ .

Let $x^{\circ}$ be the measure of the angle in question.

The supplement of this angle would be $(180 - x)^{\circ}$ .

The complement of this angle would be $(90 - x)^{\circ}$ .

According to the question:

$(180 - x) + 50 = 3\, (90 - x)$ .

Solve this equation for $x$ :

$x = 20$ .

Thus, this angle would measure should $20^{\circ}$ .

The supplement of this angle would measure $(180 - 20)^{\circ} = 160^{\circ}$ . The complement of this angle would measure $(90 - 20)^{\circ} = 70^{\circ}$ .

Three times the complement of this angle would be $3 \times 70^{\circ} = 210^{\circ}$ , which is indeed $50^{\circ}$ greater than the supplement of this angle.

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2 years ago