Question

Factorise fully 2x^2-8x

Answer 1

Answer:

$\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)$

Step-by-step explanation:

Given the expression

$2x^2-8x$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c$

$x^2=xx$

so the expression becomes

$2x^2-8x=2xx-8x$

               $=2xx-2\cdot \:4x$

               $=2x\left(x-4\right)$              ∵  $\mathrm{Factor\:out\:common\:term\:}2x$

Therefore,

$\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)$    

Answer 2

Answer:

2x(x-4)

Step-by-step explanation:

2$x^{2}$-8x= 2($x^{2}$-4x)= 2x(x-4)