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3 years ago

Factorise fully 2x^2-8x

Mathematics

2 answers:

solmaris [256]3 years ago

4 0

Answer:

$\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)$

Step-by-step explanation:

Given the expression

$2x^2-8x$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c$

$x^2=xx$

so the expression becomes

$2x^2-8x=2xx-8x$

$=2xx-2\cdot \:4x$

$=2x\left(x-4\right)$ ∵ $\mathrm{Factor\:out\:common\:term\:}2x$

Therefore,

$\mathrm{Factor}\:2x^2-8x:\:2x\left(x-4\right)$

Molodets [167]3 years ago

3 0

Answer:

2x(x-4)

Step-by-step explanation:

2 $x^{2}$ -8x= 2( $x^{2}$ -4x)= 2x(x-4)

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