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2 years ago

How do you do one-step equations?

1 answer:

6 0

An example of a one step equation would be 5+5=10
But equations with more than one step would be like: find the sum of 5+5 and then find 50% of the sum of 5+5

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PLEASE LOOK AT PHOTO! WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINIEST!!

marissa [1.9K]

Answer:

53°

Step-by-step explanation:

It is given that the total measurement of the two angles combined would equate to 116°.

It is also given that m∠WXY is 10° more then m∠ZXY.

Set the system of equation:

m∠1 + m∠2 = 116°

m∠1 = m∠2 + 10°

First, plug in "m∠2 + 10" for m∠1 in the first equation:

m∠1 + m∠2 = 116°

(m∠2 + 10) + m∠2 = 116°

Simplify. Combine like terms:

2(m∠2) + 10 = 116

Next, isolate the variable, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 10 from both sides of the equation:

2(m∠2) + 10 (-10) = 116 (-10)

2(m∠2) = 116 - 10

2(m∠2) = 106

Next, divide 2 from both sides of the equation:

(2(m∠2))/2 = (106)/2

m∠2 = 106/2 = 53°

53° is your answer.

8 0

2 years ago

Read 2 more answers

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

coldgirl [10]

Changing the equation into slope form: $y = mx + c$ , where $m$ is the slope [gradient] and $c$ is the y-intercept.

$2x+3y=1470$
$3y = -2x+1470$
$y= - \frac{2}{3}x+ \frac{1470}{3}$
$y=- \frac{2}{3}x+490$

The gradient is $- \frac{2}{3}$ and y-intercept is at $y=490$

Graphing $y=- \frac{2}{3}x+490$ using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
   $0 = - \frac{2}{3}x+490$
   $\frac{2}{3}x = 490$
   $2x = 1470$
   $x = \frac{1470}{2}$
   $x = 735$
So, x-intercept is at (735, 0)

The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735

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Next month's profit equation

$2x+3y=1593$

Rewriting this into slope-equation form

$3y = -2x+1593$
$y=- \frac{2}{3}+ \frac{1593}{3}$
$y= - \frac{2}{3}+531$

The gradient, $m$ , equals to $- \frac{2}{3}$
The y-intercept, $c$ , equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept.

-------------------------------------------------------------------------------------------------------------

A linear graph show points of (0, 300) and (450, 0)

We work out the slope:
$\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30} =- \frac{2}{3}$

Y-intercept at x = 0, so it's at y = 300

Equation $y = - \frac{2}{3}+300$